Maxima and Minima in Differentiation¶
Maxima and minima are critical points in the study of differentiation, where a function reaches its highest or lowest values within a given interval. These points are essential for understanding the behavior of functions, optimization problems, and real-world applications.
Definitions¶
- Local Maximum: A function \( f(x) \) has a local maximum at \( x = a \) if \( f(a) \) is greater than or equal to \( f(x) \) for all \( x \) in some open interval around \( a \). In other words, \( f(a) \geq f(x) \) for all \( x \) near \( a \).
- Local Minimum: A function \( f(x) \) has a local minimum at \( x = b \) if \( f(b) \) is less than or equal to \( f(x) \) for all \( x \) in some open interval around \( b \). That is, \( f(b) \leq f(x) \) for all \( x \) near \( b \).
- Global Maximum and Minimum: These are the highest and lowest values of \( f(x) \) on the entire domain.
Steps for Finding Maxima and Minima¶
- Find the First Derivative (\( f'(x) \)):
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Differentiate the function to obtain \( f'(x) \), which gives the slope of the tangent line at any point.
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Set the First Derivative Equal to Zero:
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Solve the equation \( f'(x) = 0 \) to find the critical points. These are potential points where the function could have a maximum or minimum.
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Determine the Nature of Each Critical Point:
- Use either the Second Derivative Test or the First Derivative Test to classify the critical points.
Second Derivative Test¶
- Find the second derivative, \( f''(x) \).
- Evaluate \( f''(x) \) at each critical point:
- If \( f''(x) > 0 \), the function is concave up at that point, indicating a local minimum.
- If \( f''(x) < 0 \), the function is concave down at that point, indicating a local maximum.
- If \( f''(x) = 0 \), the test is inconclusive, and you should use the first derivative test.
First Derivative Test¶
- Examine the sign of \( f'(x) \) around each critical point:
- If \( f'(x) \) changes from positive to negative, the critical point is a local maximum.
- If \( f'(x) \) changes from negative to positive, the critical point is a local minimum.
- If \( f'(x) \) does not change sign, the point is neither a maximum nor a minimum.
Example 1: Find the Maxima and Minima of \( f(x) = x^3 - 3x^2 + 4 \)¶
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Find the First Derivative: [ f'(x) = 3x^2 - 6x ]
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Set \( f'(x) = 0 \) to Find Critical Points: [ 3x^2 - 6x = 0 \implies 3x(x - 2) = 0 ] Thus, \( x = 0 \) and \( x = 2 \) are critical points.
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Apply the Second Derivative Test:
- Find the second derivative: [ f''(x) = 6x - 6 ]
- Evaluate \( f''(x) \) at \( x = 0 \) and \( x = 2 \):
- At \( x = 0 \), \( f''(0) = 6(0) - 6 = -6 \) (concave down, local maximum).
- At \( x = 2 \), \( f''(2) = 6(2) - 6 = 6 \) (concave up, local minimum).
Example 2: Find the Maxima and Minima of \( f(x) = e^x \sin(x) \)¶
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Find the First Derivative: [ f'(x) = e^x \sin(x) + e^x \cos(x) ]
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Set \( f'(x) = 0 \) to Find Critical Points: [ e^x (\sin(x) + \cos(x)) = 0 ] Since \( e^x \neq 0 \), solve \( \sin(x) + \cos(x) = 0 \).
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Classify the Critical Points Using the First Derivative Test:
- Analyze the sign changes of \( f'(x) \) around the critical points to determine if they correspond to maxima, minima, or neither.
Practical Applications¶
- Business and Economics: Finding the maximum profit or minimum cost.
- Physics: Determining the highest or lowest points of a motion trajectory.
- Engineering: Optimizing design parameters for maximum efficiency.
Maxima and minima provide critical insights into the behavior of functions, especially in optimization problems where finding the highest or lowest values is essential.
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